1864 United States presidential election in Vermont

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1864 United States presidential election in Vermont
Flag of Vermont (1837-1923).svg
  1860 November 8, 1864 1868  
  Abraham Lincoln November 1863.jpg GeorgeMcClellan2 (cropped).jpg
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote50
Popular vote42,42013,322
Percentage76.10%23.90%

Vermont Presidential Election Results 1864.svg
County Results
Lincoln
  60-70%
  70-80%
  80-90%
  90-100%

The 1864 United States presidential election in Vermont took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Vermont voted for the National Union candidate, Abraham Lincoln, over the Democratic candidate, George B. McClellan. Lincoln won the state by a wide margin of 52.20%.

With 76.10% of the popular vote, Lincoln's victory with in the state would be his second strongest victory in the country in terms of percentage in the popular vote after Kansas. [1]

Results

1864 United States presidential election in Vermont [2]
PartyCandidateVotesPercentageElectoral votes
National Union Abraham Lincoln (incumbent)42,42076.10%5
Democratic George B. McClellan 13,32223.90%0
Totals55,742100.0%26

See also

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References

  1. "1864 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. "1864 Presidential General Election Results - Vermont".