Cousin's theorem

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In real analysis, a branch of mathematics, Cousin's theorem states that:

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If for every point of a closed region (in modern terms, "closed and bounded") there is a circle of finite radius (in modern term, a "neighborhood"), then the region can be divided into a finite number of subregions such that each subregion is interior to a circle of a given set having its center in the subregion. [1]

This result was originally proved by Pierre Cousin, a student of Henri Poincaré, in 1895, and it extends the original Heine–Borel theorem on compactness for arbitrary covers of compact subsets of . However, Pierre Cousin did not receive any credit. Cousin's theorem was generally attributed to Henri Lebesgue as the Borel–Lebesgue theorem. Lebesgue was aware of this result in 1898, and proved it in his 1903 dissertation. [1]

In modern terms, it is stated as:

Let be a full cover of [a, b], that is, a collection of closed subintervals of [a, b] with the property that for every x ∈ [a, b], there exists a δ>0 so that contains all subintervals of [a, b] which contains x and length smaller than δ. Then there exists a partition of non-overlapping intervals for [a, b], where and a=x0 < x1 < ⋯ < xn=b for all 1≤in.

Cousin's lemma is studied in reverse mathematics where it is one of the first third-order theorems that is hard to prove in terms of the comprehension axioms needed.

In Henstock–Kurzweil integration

Cousin's theorem is instrumental in the study of Henstock–Kurzweil integration, and in this context, it is known as Cousin's lemma or the fineness theorem.

A gauge on is a strictly positive real-valued function , while a tagged partition of is a finite sequence [2] [3]

Given a gauge and a tagged partition of , we say is -fine if for all , we have , where denotes the open ball of radius centred at . Cousin's lemma is now stated as:

If , then every gauge has a -fine partition. [4]

Proof of the theorem

Cousin's theorem has an intuitionistic proof using the open induction principle, which reads as follows:

An open subset of a closed real interval is said to be inductive if it satisfies that implies . The open induction principle states that any inductive open subset of must be the entire set.

Proof using open induction

Let be the set of points such that there exists a -fine tagged partition on for some . The set is open, since it is downwards closed and any point in it is included in the open ray for any associated partition.

Furthermore, it is inductive. For any , suppose . By that assumption (and using that either or to handle the base case) we have a partition of length with . Then either or . In the first case , so we can just replace with and get a partition of that includes .

If , we may form a partition of length that includes . To show this, we split into the cases or . In the first case, we set , in the second we set . In both cases, we can set and obtain a valid partition. So in all cases, and is inductive.

By open induction, .

Notes

  1. 1 2 Hildebrandt 1925, p. 29
  2. Gordon, Russell (1994-08-01). The Integrals of Lebesgue, Denjoy, Perron, and Henstock. Graduate Studies in Mathematics. Vol. 4. Providence, Rhode Island: American Mathematical Society. doi:10.1090/gsm/004. ISBN   978-0-8218-3805-1.
  3. Kurtz, Douglas S; Swartz, Charles W (October 2011). "Theories of Integration". Series in Real Analysis. 13. doi:10.1142/8291. ISBN   978-981-4368-99-5. ISSN   1793-1134.
  4. Bartle 2001, p. 11

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