Semileptonic decay

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In particle physics the semileptonic decay of a hadron is a decay caused by the weak force in which one lepton (and the corresponding neutrino) is produced in addition to one or more hadrons. [1] An example for this can be

K0
  e
 + ν
e
 + π+

This is to be contrasted with purely hadronic decays, such as K0
  π+
 + π
, which are also mediated by the weak force. [2]

Semileptonic decays of neutral kaons have been used to study kaon oscillations. [3]

See also

References

  1. "Semileptonic decays and indirect probes of new physics". Imperial College London. Retrieved 2026-03-01.
  2. Griffiths, D. J. (1987). Introduction to Elementary Particle. John Wiley & Sons. ISBN   0-471-60386-4.
  3. Aoki, S.; Aoki, Y.; Bečirević, D.; Blum, T.; Colangelo, G.; Collins, S.; Della Morte, M.; Dimopoulos, P.; Dürr, S.; Fukaya, H.; Golterman, M.; Gottlieb, Steven; Gupta, R.; Hashimoto, S.; Heller, U. M. (2020-02-11). "FLAG Review 2019". The European Physical Journal C. 80 (2): 113. doi: 10.1140/epjc/s10052-019-7354-7 . ISSN   1434-6052.