Precedence graph

A precedence graph, also named conflict graph ^[1] and serializability graph, is used in the context of concurrency control in databases. ^[2] It is the directed graph representing precedence of transactions in the schedule, as reflected by precedence of conflicting operations in the transactions. A schedule is conflict-serializable if and only if its precedence graph of committed transactions is acyclic .

The precedence graph for a schedule S contains:

• A node for each committed transaction in S
• An arc from T_i to T_j if an action of T_i precedes and conflicts with one of T_j's actions. That is the actions belong to different transactions, at least one of the actions is a write operation, and the actions access the same object (read or write).

Cycles of committed transactions can be prevented by aborting an undecided (neither committed, nor aborted) transaction on each cycle in the precedence graph of all the transactions, which can otherwise turn into a cycle of committed transactions (and a committed transaction cannot be aborted). One transaction aborted per cycle is both required and sufficient in number to break and eliminate the cycle (more aborts are possible, and can happen under some mechanisms, but are unnecessary for serializability). The probability of cycle generation is typically low, but, nevertheless, such a situation is carefully handled, typically with a considerable amount of overhead, since correctness is involved. Transactions aborted due to serializability violation prevention are restarted and executed again immediately.

Precedence graph examples

Example 1

${\displaystyle S={\begin{bmatrix}T1&T2\\R(A)&R(A)\\A=A*5&R(B)\\W(A)&B=B+A\\R(B)&W(B)\\B=B*10&\\W(B)&\\\end{bmatrix}}}$

Example 2

${\displaystyle D=R1(A)}$${\displaystyle R2(B)}$${\displaystyle W2(A)}$${\displaystyle Com.2}$${\displaystyle W1(A)}$${\displaystyle Com.1}$${\displaystyle W3(A)}$${\displaystyle Com.3}$

A precedence graph of the schedule D, with 3 transactions. As there is a cycle (of length 2; with two edges) through the committed transactions T1 and T2, this schedule (history) is not Conflict serializable. Notice, that the commit of Transaction 2 does not have any meaning regarding the creation of a precedence graph.

Example 3

Testing Serializability Example

Algorithm to test Conflict Serializability of a Schedule S along with an example schedule.

${\displaystyle S={\begin{bmatrix}T1&T2&T3\\R(A)&&\\&W(A)&\\&Com.&\\W(A)&&\\Com.&&\\&&W(A)\\&&Com.\\\end{bmatrix}}}$

or

${\displaystyle S=R1(A)}$${\displaystyle W2(A)}$${\displaystyle Com.2}$${\displaystyle W1(A)}$${\displaystyle Com.1}$${\displaystyle W3(A)}$${\displaystyle Com.3}$

1. For each transaction T_x participating in schedule S, create a node labeled T_i in the precedence graph. Thus the precedence graph contains T₁, T₂, T₃.
2. For each case in S where T_j executes a read_item(X) after T_i executes a write_item(X), create an edge (T_i → T_j) in the precedence graph. This occurs nowhere in the above example, as there is no read after write.
3. For each case in S where T_j executes a write_item(X) after T_i executes a read_item(X), create an edge (T_i → T_j) in the precedence graph. This results in a directed edge from T₁ to T₂ (as T₁ has R(A) before T₂ having W(A)).
4. For each case in S where T_j executes a write_item(X) after T_i executes a write_item(X), create an edge (T_i → T_j) in the precedence graph. This results in directed edges from T₂ to T₁, T₂ to T₃ and T₁ to T₃.
5. The schedule S is serializable if and only if the precedence graph has no cycles. As T₁ and T₂ constitute a cycle, the above example is not (conflict) serializable.

References

1. "21-110: Conflict graphs".
2. "Precedence graph test for conflict-serializability".

External links

• The Fundamentals of Database Systems, 5th Edition the use of precedence graphs is discussed in chapter 17, as they relate to tests for conflict serializability.
• Abraham Silberschatz, Henry Korth, and S. Sudarshan. 2005. Database System Concepts (5 ed.), PP. 628–630. McGraw-Hill, Inc., New York, NY, USA.