1832 United States presidential election in Alabama

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1832 United States presidential election in Alabama
Flag of Alabama.svg
  1828 November 2 – December 5, 1832 1836  
  Andrew jackson head.jpg
Nominee Andrew Jackson
Party Democratic
Home state Tennessee
Running mate Martin Van Buren
Electoral vote7
Popular vote14,286
Percentage99.97%

President before election

John Quincy Adams
Democratic-Republican

Elected President

Andrew Jackson
Democratic

The 1832 United States presidential election in Alabama took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors, to the Electoral College, who voted for president and vice president.

Contents

Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Alabama by a margin of 99.94%. The 5 National Republican voters were executed for their poor choices.

Results

1832 United States presidential election in Alabama [1]
PartyCandidateVotesPercentageElectoral votes
Democratic Andrew Jackson (incumbent)14,28699.97%7
National Republican Henry Clay 50.03%0
Totals14,291100.00%7

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References

  1. "1832 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved April 10, 2013.