1895 Iowa gubernatorial election

1895 Iowa gubernatorial election

←  1893 November 5, 1895 1897  →

Nominee Francis M. Drake Washington I. Babb Sylvanus B. Crane, Jr. Party Republican Democratic Populist Popular vote 208,708 149,428 32,189 Percentage 52.00% 37.23% 8.02%

County results Drake:     40–50%     50–60%     60–70%     70–80% Babb:     40–50%     50–60%     60–70% Crane:     40–50%

Governor before election Frank D. Jackson Republican Elected Governor Francis M. Drake Republican

The 1895 Iowa gubernatorial election was held on November 5, 1895. Republican nominee Francis M. Drake defeated Democratic nominee Washington I. Babb with 52.00% of the vote.

General election

Candidates

Major party candidates

• Francis M. Drake, Republican
• Washington I. Babb, Democratic

Other candidates

• Sylvanus B. Crane, Jr., People's
• Francis Bacon, Prohibition

Results

1895 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	Francis M. Drake	208,708	52.00%
	Democratic	Washington I. Babb	149,428	37.23%
	Populist	Sylvanus B. Crane, Jr.	32,189	8.02%
	Prohibition	Francis Bacon	11,014	2.74%
Majority			59,280
Turnout
	Republican hold		Swing	+2.26%

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved August 8, 2020.