1876 United States presidential election in Vermont

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1876 United States presidential election in Vermont
Flag of Vermont (1837-1923).svg
  1872 November 7, 1876 1880  
  President Rutherford Hayes 1870 - 1880 Restored (cropped).jpg SamuelJonesTilden.jpg
Nominee Rutherford B. Hayes Samuel J. Tilden
Party Republican Democratic
Home state Ohio New York
Running mate William A. Wheeler Thomas A. Hendricks
Electoral vote50
Popular vote44,09120,254
Percentage68.30%31.38%

Vermont Presidential Election Results 1876.svg
County Results
Hayes
  50–60%
  60–70%
  70–80%
  80–90%

The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.

With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote. [1]

Results

1876 United States presidential election in Vermont [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Republican Rutherford B. Hayes of Ohio William A. Wheeler of New York 44,09168.30%5100.00%
Democratic Samuel J. Tilden of New York Thomas A. Hendricks of Indiana 20,25431.38%00.00%
N/AOthersOthers2080.32%00.00%
Total64,553100.00%5100.00%

See also

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References

  1. "1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. "1876 Presidential General Election Results - Vermont".