Glasgow – Doubles | |
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2019 Murray Trophy – Glasgow | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Score | 4–6, 6–3, [10–8] |
Gerard Granollers and Guillermo Olaso were the defending champions [1] but chose not to defend their title.
Ruben Bemelmans and Daniel Masur won the title after defeating Jamie Murray and John-Patrick Smith 4–6, 6–3, [10–8] in the final.
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
WC | ![]() ![]() | 4 | 2 | 1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||
Alt | ![]() ![]() | 77 | 78 | Alt | ![]() ![]() | 3 | 4 | ||||||||||||||||||||
![]() ![]() | 65 | 66 | 1 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
4 | ![]() ![]() | 3 | 6 | [10] | ![]() ![]() | 2 | 3 | ||||||||||||||||||||
WC | ![]() ![]() | 6 | 3 | [3] | 4 | ![]() ![]() | 4 | 6 | [3] | ||||||||||||||||||
![]() ![]() | 7 | 79 | ![]() ![]() | 6 | 3 | [10] | |||||||||||||||||||||
![]() ![]() | 5 | 67 | 1 | ![]() ![]() | 6 | 3 | [8] | ||||||||||||||||||||
![]() ![]() | w/o | ![]() ![]() | 4 | 6 | [10] | ||||||||||||||||||||||
![]() ![]() | ![]() ![]() | ||||||||||||||||||||||||||
![]() ![]() | 77 | 6 | ![]() ![]() | w/o | |||||||||||||||||||||||
3 | ![]() ![]() | 62 | 4 | ![]() ![]() | 6 | 4 | [11] | ||||||||||||||||||||
![]() ![]() | 64 | 5 | 2 | ![]() ![]() | 4 | 6 | [9] | ||||||||||||||||||||
![]() ![]() | 77 | 7 | ![]() ![]() | 4 | 2 | ||||||||||||||||||||||
![]() ![]() | 4 | 63 | 2 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||
2 | ![]() ![]() | 6 | 77 |