Doubles | |
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1985 Virginia Slims of Chicago | |
Champions | ![]() ![]() |
Runners-up | ![]() ![]() |
Score | 6–2, 6–2 |
Draw | 16 |
Seeds | 4 |
Billie Jean King and Sharon Walsh-Pete were the defending champions, but King did not compete this year. Walsh-Pete teamed up with Barbara Potter and lost in the semifinals to Elise Burgin and JoAnne Russell
Kathy Jordan and Elizabeth Smylie won the title by defeating Burgin and Russell 6–2, 6–2 in the final. [1]
First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||||||
![]() ![]() | 1 | 3 | 1 | ![]() ![]() | 6 | 7 | |||||||||||||||||||||
![]() ![]() | 4 | 7 | 6 | ![]() ![]() | 4 | 6 | |||||||||||||||||||||
![]() ![]() | 6 | 5 | 2 | 1 | ![]() ![]() | 6 | 6 | 6 | |||||||||||||||||||
4 | ![]() ![]() | 6 | 4 | 6 | 4 | ![]() ![]() | 7 | 2 | 3 | ||||||||||||||||||
![]() ![]() | 1 | 6 | 2 | 4 | ![]() ![]() | 6 | 6 | ||||||||||||||||||||
![]() ![]() | w/o | ![]() ![]() | 1 | 1 | |||||||||||||||||||||||
![]() ![]() | 1 | ![]() ![]() | 6 | 6 | |||||||||||||||||||||||
![]() ![]() | 6 | 6 | ![]() ![]() | 2 | 2 | ||||||||||||||||||||||
![]() ![]() | 4 | 4 | ![]() ![]() | 6 | 4 | 4 | |||||||||||||||||||||
![]() ![]() | 3 | 2 | 3 | ![]() ![]() | 2 | 6 | 6 | ||||||||||||||||||||
3 | ![]() ![]() | 6 | 6 | 3 | ![]() ![]() | 6 | 2 | ||||||||||||||||||||
![]() ![]() | 3 | 6 | 6 | ![]() ![]() | 7 | 6 | |||||||||||||||||||||
![]() ![]() | 6 | 3 | 4 | ![]() ![]() | w/o | ||||||||||||||||||||||
![]() ![]() | 3 | 0 | 2 | ![]() ![]() | |||||||||||||||||||||||
2 | ![]() ![]() | 6 | 6 |
In the doubles final, Kathy Jordan and Elizabeth Smylie beat Elise Burgin and JoAnne Russell, 6-2, 6-2.