| Tournament details | |
|---|---|
| Host country | Guatemala |
| City | Guatemala City |
| Dates | July 15 – 20 |
| Teams | 4 (from 3 associations) |
| Final positions | |
| Champions |  Cruz Azul (4th title) |
| Runners-up | Necaxa |
| Tournament statistics | |
| Matches played | 6 |
| Goals scored | 29 (4.83 per match) |
← 1995 1997 → | |
The 1996 CONCACAF Champions' Cup was the 32nd edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region and was played from March 9, 1996, through July 20, 1997.
Contents
- North/Central American Zone
- Group 1
- Group 2
- Group 3
- Caribbean Zone
- First round
- Second round
- U.S./Caribbean Playoff
- Final group stage
- Matches
- Champion
- References
The teams were split into 2 zones (North/ Central and Caribbean). The North/Central zone was split into 3 groups, qualifying each winner to the final tournament. The winner of the Caribbean zone, earned a place in a playoff against the U.S. representative for a spot in the final tournament. All qualifying matches in the tournament were played under the home/away match system, while the final tournament was played in Guatemala City.
That final stage composed of four teams which played each other in a single round-robin tournament. Mexican team Cruz Azul won their fourth CONCACAF trophy, after finishing 1st. in the final table with 7 points over 3 matches played. [1]
