Sherman Township, Hardin County, Iowa

Sherman Township
Township
Coordinates: 42°20′23″N093°24′17″W / 42.33972°N 93.40472°W / 42.33972; -93.40472
Country	United States
State	Iowa
County	Hardin
Area
• Total	35.98 sq mi (93.19 km2)
• Land	35.98 sq mi (93.19 km2)
• Water	0 sq mi (0 km2)
Elevation [1]	1,142 ft (348 m)
Population  (2000)
• Total	461
• Density	13.2/sq mi (5.1/km2)
FIPS code	468 697 [2] [3]
GNIS feature ID	0468696

Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738. ^{[4] [1]}

History

Sherman Township was founded in 1870. ^[5] It is named for William Tecumseh Sherman. ^[6]

References

1. "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
2. "U.S. Census website". United States Census Bureau . Retrieved January 31, 2008.
3. U.S. Geological Survey Geographic Names Information System: Sherman Township, Hardin County, Iowa
4. "Find a County". National Association of Counties. Retrieved June 7, 2011.
5. Moir, William J. (1911). Past and Present of Hardin County, Iowa. Unigraphic. pp.  319.
6. History of Hardin County, Iowa. Union Publishing Company. 1883. pp.  904.