Consider an operation that transforms a particle into its antiparticle,
Both states must be normalizable, so that
which implies that is unitary,
By acting on the particle twice with the operator,
we see that and . Putting this all together, we see that
meaning that the charge conjugation operator is Hermitian and therefore a physically observable quantity.
Eigenvalues
For the eigenstates of charge conjugation,
.
As with parity transformations, applying twice must leave the particle's state unchanged,
allowing only eigenvalues of the so-called C-parity or charge parity of the particle.
Eigenstates
The above implies that for eigenstates, Since antiparticles and particles have charges of opposite sign, only states with all quantum charges equal to zero, such as the photon and particle–antiparticle bound states like π0, η0, or positronium, are eigenstates of
Multiparticle systems
For a system of free particles, the C parity is the product of C parities for each particle.
In a pair of bound mesons there is an additional component due to the orbital angular momentum. For example, in a bound state of two pions, π+ π− with an orbital angular momentumL, exchanging π+ and π− inverts the relative position vector, which is identical to a parity operation. Under this operation, the angular part of the spatial wave function contributes a phase factor of (−1)L, where L is the angular momentum quantum number associated with L.
.
With a two-fermion system, two extra factors appear: One factor comes from the spin part of the wave function, and the second by considering the intrinsic parities of both the particles. Note that a fermion and an antifermion always have opposite intrinsic parity. Hence,
positronium is a bound state electron-positron similar to a hydrogenatom. The names parapositronium and orthopositronium are given to the states 1S0 and 3S1.
With S = 0, the spins are anti-parallel, and with S = 1 they are parallel. This gives a multiplicity ( 2 S + 1 ) of 1 (anti-parallel) or 3 (parallel)
C parity ηC = (−1)L + S = +1 or −1 , depending on L and S. Since charge parity is preserved, annihilation of these states in photons( ηC(γ) = −1 ) must be:
Orbital:
1S0 → γ + γ
3S1 → γ + γ + γ
ηC:
+1 = (−1) × (−1)
−1 = (−1) × (−1) × (−1)
Experimental tests of C-parity conservation
: The neutral pion, , is observed to decay to two photons, γ+γ . We can infer that the pion therefore has but each additional γ introduces a factor of −1 to the overall C-parity of the pion. The decay to 3γ would violate C parity conservation. A search for this decay was conducted[1] using pions created in the reaction
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