Harlan Township, Fayette County, Iowa

Last updated

Harlan Township
Township
Map highlighting Harlan Township, Fayette County, Iowa.svg
Location in Fayette County
Coordinates: 42°46′51″N91°54′45″W / 42.78083°N 91.91250°W / 42.78083; -91.91250
Country Flag of the United States (23px).png  United States
State Flag of Iowa.svg Iowa
County Fayette
Area
 • Total
36.79 sq mi (95.28 km2)
 • Land36.76 sq mi (95.22 km2)
 • Water0.027 sq mi (0.07 km2)  0.07%
Elevation
1,145 ft (349 m)
Population
 (2010)
 • Total
871
 • Density23.7/sq mi (9.15/km2)
Time zone UTC-6 (CST)
 • Summer (DST) UTC-5 (CDT)
ZIP codes
50655, 50662, 50681, 52142, 52164
GNIS feature ID 0468005

Harlan Township is one of twenty townships in Fayette County, Iowa. As of the 2010 census, its population was 871. [1]

Contents

Geography

According to the United States Census Bureau, Harlan Township covers an area of 36.79 square miles (95.28 square kilometers); of this, 36.76 square miles (95.22 square kilometers, 99.94 percent) is land and 0.03 square miles (0.07 square kilometers, 0.07 percent) is water.

Cities, towns, villages

Adjacent townships

Cemeteries

The township contains these two cemeteries: Hope and Long Grove.

Major highways

Landmarks

School districts

Political districts

References

  1. ↑ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Harlan township, Fayette County, Iowa". United States Census Bureau . Retrieved March 5, 2012.
This page is based on this Wikipedia article
Text is available under the CC BY-SA 4.0 license; additional terms may apply.
Images, videos and audio are available under their respective licenses.