Harlan Township, Fayette County, Iowa

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Harlan Township
Map highlighting Harlan Township, Fayette County, Iowa.svg
Location in Fayette County
Coordinates: 42°46′51″N91°54′45″W / 42.78083°N 91.91250°W / 42.78083; -91.91250
Country Flag of the United States.svg  United States
State Flag of Iowa.svg  Iowa
County Fayette
Area
  Total36.79 sq mi (95.28 km2)
  Land36.76 sq mi (95.22 km2)
  Water0.03 sq mi (0.07 km2)  0.07%
Elevation
1,145 ft (349 m)
Population
 (2010)
  Total871
  Density24/sq mi (9.1/km2)
Time zone UTC-6 (CST)
  Summer (DST) UTC-5 (CDT)
ZIP codes
50655, 50662, 50681, 52142, 52164
GNIS feature ID 0468005

Harlan Township is one of twenty townships in Fayette County, Iowa. As of the 2010 census, its population was 871. [1]

Contents

Geography

According to the United States Census Bureau, Harlan Township covers an area of 36.79 square miles (95.28 square kilometers); of this, 36.76 square miles (95.22 square kilometers, 99.94 percent) is land and 0.03 square miles (0.07 square kilometers, 0.07 percent) is water.

Cities, towns, villages

Adjacent townships

Cemeteries

The township contains these two cemeteries: Hope and Long Grove.

Major highways

Landmarks

School districts

Political districts

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References

  1. "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Harlan township, Fayette County, Iowa". United States Census Bureau . Retrieved March 5, 2012.