Graham Township, Iowa | |
---|---|
Coordinates: 41°43′46″N91°24′55″W / 41.72944°N 91.41528°W | |
Country | United States |
State | Iowa |
County | Johnson |
Area | |
• Total | 30.3 sq mi (78.5 km2) |
• Land | 30.3 sq mi (78.5 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Population | |
• Total | 494 |
• Density | 16.30/sq mi (5.37/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
Graham Township is a township in Johnson County, Iowa, United States. [2]
Graham Township was organized in 1857. It is named after John Graham, an early settler. [3]
As of the 2020 Census, there were 494 people and 256 households in the community. The population density was 16.30 inhabitants per square mile (6.29 inhabitants/km2).
The median age in the city was 53.9 years.
Year | Democratic | Republican | Third Parties |
---|---|---|---|
2020 [4] | 62.84%208 | 35.65% 118 | 3.02% 10 |
2016 [5] | 56.92%185 | 37.54% 122 | 5.54% 18 |
2012 [6] | 61.92%187 | 35.43% 107 | 2.65% 8 |
2008 [7] | 63.56%143 | 32.89% 74 | 3.56% 8 |
2004 [8] | 56.34%120 | 40.38% 86 | 3.29% 7 |
2000 [9] | 61.19%123 | 30.85% 62 | 7.96% 16 |
1996 [10] | 59.90%124 | 27.05% 56 | 13.04% 27 |
1992 [11] | 49.13%113 | 18.70% 43 | 32.17% 74 |
1988 [12] | 79.02%177 | 20.98% 47 | 0.00% 0 |
1984 [13] | 65.97%157 | 34.03% 81 | 0.00% 0 |
1980 [14] | 51.38%112 | 34.40% 75 | 14.22% 31 |
1976 [15] | 61.19%123 | 34.83% 70 | 3.98% 8 |
1972 [16] | 56.55%95 | 43.45% 73 | 0.00% 0 |
1968 [17] | 55.56%115 | 36.71% 76 | 7.73% 16 |
1964 [18] | 70.81%148 | 29.19% 61 | 0.00% 0 |
1960 [19] | 62.61%144 | 37.39% 86 | 0.00% 0 |
1956 [20] | 65.31%160 | 34.69% 85 | 0.00% 0 |
1952 [21] | 53.78%135 | 46.22% 116 | 0.00% 0 |
1948 [22] | 63.37%154 | 34.98% 85 | 1.65% 4 |
1944 [23] | 64.32%137 | 35.68% 76 | 0.00% 0 |