Time derivative

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A time derivative is a derivative of a function with respect to time, usually interpreted as the rate of change of the value of the function. [1] The variable denoting time is usually written as ${\displaystyle t}$.

Notation

A variety of notations are used to denote the time derivative. In addition to the normal (Leibniz's) notation,

${\displaystyle {\frac {dx}{dt}}}$

A very common short-hand notation used, especially in physics, is the 'over-dot'. I.E.

${\displaystyle {\dot {x}}}$

(This is called Newton's notation)

Higher time derivatives are also used: the second derivative with respect to time is written as

${\displaystyle {\frac {d^{2}x}{dt^{2}}}}$

with the corresponding shorthand of ${\displaystyle {\ddot {x}}}$.

As a generalization, the time derivative of a vector, say:

${\displaystyle \mathbf {v} =\left[v_{1},\ v_{2},\ v_{3},\ldots \right]}$

is defined as the vector whose components are the derivatives of the components of the original vector. That is,

${\displaystyle {\frac {d\mathbf {v} }{dt}}=\left[{\frac {dv_{1}}{dt}},{\frac {dv_{2}}{dt}},{\frac {dv_{3}}{dt}},\ldots \right].}$

Use in physics

Time derivatives are a key concept in physics. For example, for a changing position ${\displaystyle x}$, its time derivative ${\displaystyle {\dot {x}}}$ is its velocity, and its second derivative with respect to time, ${\displaystyle {\ddot {x}}}$, is its acceleration. Even higher derivatives are sometimes also used: the third derivative of position with respect to time is known as the jerk. See motion graphs and derivatives.

A large number of fundamental equations in physics involve first or second time derivatives of quantities. Many other fundamental quantities in science are time derivatives of one another:

and so on.

A common occurrence in physics is the time derivative of a vector, such as velocity or displacement. In dealing with such a derivative, both magnitude and orientation may depend upon time.

Example: circular motion

For example, consider a particle moving in a circular path. Its position is given by the displacement vector ${\displaystyle r=x{\hat {\imath }}+y{\hat {\jmath }}}$, related to the angle, θ, and radial distance, r, as defined in the figure:

{\displaystyle {\begin{aligned}x&=r\cos(\theta )\\y&=r\sin(\theta )\end{aligned}}}

For this example, we assume that θ = t. Hence, the displacement (position) at any time t is given by

${\displaystyle \mathbf {r} (t)=r\cos(t){\hat {\imath }}+r\sin(t){\hat {\jmath }}}$

This form shows the motion described by r(t) is in a circle of radius r because the magnitude of r(t) is given by

${\displaystyle |\mathbf {r} (t)|={\sqrt {\mathbf {r} (t)\cdot \mathbf {r} (t)}}={\sqrt {x(t)^{2}+y(t)^{2}}}=r\,{\sqrt {\cos ^{2}(t)+\sin ^{2}(t)}}=r}$

using the trigonometric identity sin2(t) + cos2(t) = 1 and where ${\displaystyle \cdot }$ is the usual Euclidean dot product.

With this form for the displacement, the velocity now is found. The time derivative of the displacement vector is the velocity vector. In general, the derivative of a vector is a vector made up of components each of which is the derivative of the corresponding component of the original vector. Thus, in this case, the velocity vector is:

{\displaystyle {\begin{aligned}\mathbf {v} (t)={\frac {d\,\mathbf {r} (t)}{dt}}&=r\left[{\frac {d\,\cos(t)}{dt}},{\frac {d\,\sin(t)}{dt}}\right]\\&=r\ [-\sin(t),\ \cos(t)]\\&=[-y(t),x(t)].\end{aligned}}}

Thus the velocity of the particle is nonzero even though the magnitude of the position (that is, the radius of the path) is constant. The velocity is directed perpendicular to the displacement, as can be established using the dot product:

${\displaystyle \mathbf {v} \cdot \mathbf {r} =[-y,x]\cdot [x,y]=-yx+xy=0\,.}$

Acceleration is then the time-derivative of velocity:

${\displaystyle \mathbf {a} (t)={\frac {d\,\mathbf {v} (t)}{dt}}=[-x(t),-y(t)]=-\mathbf {r} (t)\,.}$

The acceleration is directed inward, toward the axis of rotation. It points opposite to the position vector and perpendicular to the velocity vector. This inward-directed acceleration is called centripetal acceleration.

In differential geometry

In differential geometry, quantities are often expressed with respect to the local covariant basis, ${\displaystyle \mathbf {e} _{i}}$, where i ranges over the number of dimensions. The components of a vector ${\displaystyle \mathbf {U} }$ expressed this way transform as a contravariant tensor, as shown in the expression ${\displaystyle \mathbf {U} =U^{i}\mathbf {e} _{i}}$, invoking Einstein summation convention. If we want to calculate the time derivatives of these components along a trajectory, so that we have ${\displaystyle \mathbf {U} (t)=U^{i}(t)\mathbf {e} _{i}(t)}$, we can define a new operator, the invariant derivative ${\displaystyle \delta }$, which will continue to return contravariant tensors: [2]

{\displaystyle {\begin{aligned}{\frac {\delta U^{i}}{\delta t}}={\frac {dU^{i}}{dt}}+V^{j}\Gamma _{jk}^{i}U^{k}\\\end{aligned}}}

where ${\displaystyle V^{j}={\frac {dx^{j}}{dt}}}$ (with ${\displaystyle x^{j}}$ being the jth coordinate) captures the components of the velocity in the local covariant basis, and ${\displaystyle \Gamma _{jk}^{i}}$ are the Christoffel symbols for the coordinate system. Note that explicit dependence on t has been repressed in the notation. We can then write:

{\displaystyle {\begin{aligned}{\frac {d\mathbf {U} }{dt}}={\frac {\delta U^{i}}{\delta t}}\mathbf {e} _{i}\\\end{aligned}}}

as well as:

{\displaystyle {\begin{aligned}{\frac {d^{2}\mathbf {U} }{dt^{2}}}={\frac {\delta ^{2}U^{i}}{\delta t^{2}}}\mathbf {e} _{i}\\\end{aligned}}}

In terms of the covariant derivative, ${\displaystyle \nabla _{j}}$, we have:

{\displaystyle {\begin{aligned}{\frac {\delta U^{i}}{\delta t}}=V^{j}\nabla _{j}U^{i}\\\end{aligned}}}

Use in economics

In economics, many theoretical models of the evolution of various economic variables are constructed in continuous time and therefore employ time derivatives. [3] :ch. 1-3 One situation involves a stock variable and its time derivative, a flow variable. Examples include:

Sometimes the time derivative of a flow variable can appear in a model:

• The growth rate of output is the time derivative of the flow of output divided by output itself.
• The growth rate of the labor force is the time derivative of the labor force divided by the labor force itself.

And sometimes there appears a time derivative of a variable which, unlike the examples above, is not measured in units of currency:

• The time derivative of a key interest rate can appear.
• The inflation rate is the growth rate of the price level—that is, the time derivative of the price level divided by the price level itself.

Related Research Articles

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In physics, Lagrangian mechanics is a formulation of classical mechanics founded on the stationary-action principle. It was introduced by the Italian-French mathematician and astronomer Joseph-Louis Lagrange in his 1788 work, Mécanique analytique.

In classical mechanics, the central-force problem is to determine the motion of a particle in a single central potential field. A central force is a force that points from the particle directly towards a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In a few important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.

References

1. Chiang, Alpha C., Fundamental Methods of Mathematical Economics, McGraw-Hill, third edition, 1984, ch. 14, 15, 18.
2. Grinfeld, Pavel. "Tensor Calculus 6d: Velocity, Acceleration, Jolt and the New δ/δt-derivative". YouTube . Archived from the original on 2021-12-13.
3. See for example Romer, David (1996). Advanced Macroeconomics. McGraw-Hill. ISBN   0-07-053667-8.