1892 United States presidential election in Illinois

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1892 United States presidential election in Illinois
Flag of Illinois (1915-1969).svg
  1888 November 8, 1892 1896  
  StephenGroverCleveland.png Benjamin Harrison 1896.jpg
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson I Whitelaw Reid
Electoral vote240
Popular vote426,281399,288
Percentage48.79%45.70%

Illinois Presidential Election Results 1892.svg
County Results

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Illinois took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.

Contents

Illinois was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. This marked the first time a Democratic candidate won Illinois since 1856 when James Buchanan carried the state. This makes Illinois one of three states (along with California and Wisconsin) that Cleveland lost in his first two electoral bids but won in his third.

Results

1892 United States presidential election in Illinois [1]
PartyCandidateVotesPercentageElectoral votes
Democratic Grover Cleveland 426,28148.79%24
Republican Benjamin Harrison (incumbent)399,28845.70%0
Prohibition John Bidwell 25,8712.96%0
Populist James B. Weaver 22,2072.54%0
Totals873,647100.00%24
Voter turnout

See also

Notes

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    References

    1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Illinois