Bloomfield, Wisconsin | |
|---|---|
Village | |
| Location of Bloomfield in Walworth County, Wisconsin. | |
| Coordinates: 42°32′56″N88°21′08″W / 42.54889°N 88.35222°W | |
| Country | United States |
| State | Wisconsin |
| County | Walworth |
| Area | |
• Total | 13.00 sq mi (33.67 km2) |
| • Land | 12.51 sq mi (32.39 km2) |
| • Water | 0.49 sq mi (1.28 km2) |
| Elevation | 863 ft (263 m) |
| Population (2020) | |
• Total | 4,781 |
| • Density | 379.6/sq mi (146.55/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Area code | 262 |
| FIPS code | 55-08265 |
| GNIS feature ID | 2711667 [2] |
| Website | https://villageofbloomfield.com/ |
Bloomfield is a village in Walworth County, Wisconsin, United States. [2] The village was created on December 20, 2011, from unincorporated areas of the Town of Bloomfield. It includes all of the Pell Lake census-designated place and part of the Powers Lake census-designated place. [3] The population was 4,781 as of the 2020 census. [4]
According to the United States Census Bureau, Bloomfield had a population of 4,781 as of 2020. It had approximately 2,078 households, with 1,684 families living in them. [5] 518 residents of Bloomfield were reported to be Hispanic or Latino. [6]
| Census | Pop. | Note | %± |
|---|---|---|---|
| 2020 | 4,781 | — | |
| U.S. Decennial Census [7] | |||