1890 Idaho gubernatorial election

1890 Idaho gubernatorial election

October 1, 1890 1892  →

Nominee George L. Shoup Benjamin Wilson Party Republican Democratic Popular vote 10,262 7,948 Percentage 56.35% 43.65%

County results Shoup:     50–60%     60–70% Wilson:     50–60%

Governor before election George L. Shoup (Territorial) Republican Elected Governor George L. Shoup Republican

The 1890 Idaho gubernatorial election was held on October 1, 1890, in order to elect the first governor of Idaho upon Idaho acquiring statehood in July 1890. Incumbent Republican governor of the Idaho Territory George L. Shoup defeated Democratic nominee Benjamin Wilson. ^[1]

General election

On election day, October 1, 1890, Republican nominee George L. Shoup won the election by a margin of 2,314 votes against his opponent Democratic nominee Benjamin Wilson, thereby retaining Republican control over the new office of governor. Shoup was sworn in as the first governor of the new state of Idaho on December 8, 1890. ^[2]

Results

Idaho gubernatorial election, 1890

Party		Candidate	Votes	%
	Republican	George L. Shoup (incumbent [a] )	10,262	56.35%
	Democratic	Benjamin Wilson	7,948	43.65%
Total votes			18,210	100.00%
	Republican hold

Notes

1. Incumbent governor of Idaho Territory.

References

1. "George L. Shoup". National Governors Association. Retrieved 2023-05-12.
2. "ID Governor". ourcampaigns.com. September 26, 2005. Retrieved 2023-05-12.