1890 United States House of Representatives election in Wyoming

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1890 United States House of Representatives elections in Wyoming
Flag of Wyoming.svg
September 11, 1890 (1890-09-11) 1892  
  Senator Clarence Don Clark3.jpg George T. Beck.png
Nominee Clarence D. Clark George T. Beck
Party Republican Democratic
Popular vote9,0876,520
Percentage58.22%41.78%

Elected U.S. Representative

Clarence D. Clark
Republican

There were two United States House of Representatives elections in Wyoming in 1890, both held on September 11, 1890. Republican lawyer Clarence D. Clark defeated Democratic George T. Beck with 58.22% of the vote and became the first person to represent Wyoming in the House of Representatives.

Results

United States House of Representatives election in Wyoming, 1890 [1]
PartyCandidateVotes%
Republican Clarence D. Clark 9,087 58.22%
Democratic George T. Beck 6,52041.78%
Total votes15,607 100%

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References

  1. "United States House of Representatives election in Wyoming, 1890".