1894 United States House of Representatives election in Wyoming

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1894 United States House of Representatives election in Wyoming
Flag of Wyoming.svg
  1892 November 6, 1894 (1894-11-06) 1896  
  FranklinWMondell.jpg Henry A. Coffeen.png
Nominee Frank Wheeler Mondell Henry A. Coffeen Shakespeare E. Sealey
Party Republican Democratic Populist
Popular vote10,0686,1522,906
Percentage52.64%32.17%15.19%

1894 Wyoming At-Large election results.svg
County results
Mondell:     40–50%     50–60%     60–70%
Coffeen:     30–40%
     No Data

U.S. Representative before election

Henry A. Coffeen
Democratic

Elected U.S. Representative

Frank Wheeler Mondell
Republican

The Wyoming United States House election for 1894 was held on November 6, 1894. Republican Frank Wheeler Mondell defeated Democratic incumbent Henry A. Coffeen and Populist Shakespeare E. Sealey with 52.64% of the vote making Coffeen the second incumbent Representative from Wyoming to lose reelection.

Results

United States House of Representatives election in Wyoming, 1894 [1]
PartyCandidateVotes%
Republican Frank Wheeler Mondell 10,068 52.64%
Democratic Henry A. Coffeen (inc.)6,15232.17%
Populist Shakespeare E. Sealey2,90615.19%
Total votes19,126 100%

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References

  1. "United States House of Representatives election in Wyoming, 1894".