1892 United States House of Representatives election in Wyoming

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1892 United States House of Representatives election in Wyoming
Flag of Wyoming.svg
  1890 November 8, 1892 (1892-11-08) 1894  
  Henry A. Coffeen.png Senator Clarence Don Clark3.jpg
Nominee Henry A. Coffeen Clarence D. Clark
Party Democratic Republican
Popular vote8,8558,394
Percentage51.34%48.66%

1892 Wyoming At-Large election results.svg
County results
Coffeen:     50–60%     60–70%
Clark:     50–60%
     No Data

U.S. Representative before election

Clarence D. Clark
Republican

Elected U.S. Representative

Henry A. Coffeen
Democratic

The Wyoming United States House election for 1892 was held on November 3, 1892. Democratic Henry A. Coffeen defeated Republican incumbent Clarence D. Clark with 51.34% of the vote making Clark the first incumbent Representative from Wyoming to lose reelection.

Results

United States House of Representatives election in Wyoming, 1892 [1]
PartyCandidateVotes%
Democratic Henry A. Coffeen 8,855 51.34%
Republican Clarence D. Clark (inc.)8,39448.66%
Total votes17,249 100%

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References

  1. "United States House of Representatives election in Wyoming, 1892".