1892 United States presidential election in Delaware

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1892 United States presidential election in Delaware
Flag of Delaware.svg
  1888 November 8, 1892 1896  
  StephenGroverCleveland.jpg Benjamin Harrison 1896.jpg
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson I Whitelaw Reid
Electoral vote30
Popular vote18,58118,077
Percentage49.90%48.55%

Delaware Presidential Election Results 1892.svg
County Results
Cleveland
  40-50%
  50-60%

The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Contents

Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Despite reclaiming the presidency, Cleveland performed much worse in Delaware than he did in his 1888 re-election bid. The State shifted 10 points for Harrison, voting for Cleveland by only 1.4 percentage points. This would be one of four states where Harrison outperformed his initial run for the presidency in 1888, these other states were New Hampshire, Georgia and, South Carolina.

Results

1892 United States presidential election in Delaware [1]
PartyCandidateVotesPercentageElectoral votes
Democratic Grover Cleveland 18,58149.90%3
Republican Benjamin Harrison (incumbent)18,07748.55%0
Prohibition John Bidwell 5641.51%0
Write-ins Scattered130.03%0
Totals37,235100.00%3
Voter turnout

See also

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