1840 United States presidential election in Delaware

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1840 United States presidential election in Delaware
Flag of Delaware.svg
  1836 October 30 - December 2, 1840 1844  
  William Henry Harrison crop.jpg Martin Van Buren circa 1837 crop.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote30
Popular vote5,9674,872
Percentage54.99%44.89%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in Delaware took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Delaware voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Delaware by a margin of 10.1%.

Results

1840 United States presidential election in Delaware [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Whig William Henry Harrison of Ohio John Tyler of Virginia 5,96754.99%3100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 4,87244.89%00.00%
N/AOthersOthers130.12%00.00%
Total10,852100.00%3100.00%

Results by county

1840 United States presidential election in Delaware [2]
CountyWilliam Henry Harrison

Whig

Martin Van Buren

Democratic

Various candidates

Other parties

MarginTotal votes cast
#%#%#%#%
Kent1,59359.20%1,09540.69%30.11%49818.51%2,691
New Castle2,32151.28%2,19548.50%100.22%1262.78%4,526
Sussex2,05356.48%1,58243.52%00.00%47112.96%3,635
Total:5,96754.99%4,87244.89%130.12%1,09510.09%10,852

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References

  1. "1840 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 23 December 2013.
  2. Burnham, Walter Dean (1955). Presidential ballots, 1836-1892. Internet Archive. Baltimore, Johns Hopkins Press. p. 320.