1840 United States presidential election in New Jersey

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1840 United States presidential election in New Jersey
Flag of New Jersey.svg
  1836 October 30 - December 2, 1840 1844  
  William Henry Harrison crop.jpg Martin Van Buren circa 1837 crop.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote80
Popular vote33,35131,034
Percentage51.74%48.15%

New Jersey Presidential Election Results 1840.svg
County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in New Jersey took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

New Jersey voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won New Jersey by a narrow margin of 3.59%.

Results

1840 United States presidential election in New Jersey [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Whig William Henry Harrison of Ohio John Tyler of Virginia 33,35151.74%8100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 31,03448.15%00.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 690.11%00.00%
Total64,454100.00%8100.00%

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References

  1. "1840 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved December 23, 2013.