1840 United States presidential election in New York

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1840 United States presidential election in New York
Flag of New York (1778-1901).svg
  1836 October 30 – December 2, 1840 1844  
Turnout91.9% [1] Increase2.svg 21.4 pp
  William Henry Harrison crop.jpg Martin Van Buren circa 1837 crop.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote420
Popular vote226,001212,733
Percentage51.18%48.18%

New York Presidential Election Results 1840.svg
County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

The 1840 United States presidential election in New York took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 42 representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

New York voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won New York by a narrow margin of 3.00%.

Results

1840 United States presidential election in New York [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Whig William Henry Harrison of Ohio John Tyler of Virginia 226,00151.18%42100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 212,73348.18%00.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 2,8090.64%00.00%
Total441,543100.00%42100.00%

See also

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References

  1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. "1840 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved December 23, 2013.