1800 United States presidential election in New York

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1800 United States presidential election in New York
Flag of New York (1778-1901).svg
  1796 October 31 – December 3, 1800 1804  
  Thomas Jefferson by Rembrandt Peale, 1800.jpg
Nominee Thomas Jefferson
Party Democratic-Republican
Home state Virginia
Running mate Aaron Burr
Electoral vote12
Percentage100.00%

President before election

John Adams
Federalist

Elected President

Thomas Jefferson
Democratic-Republican

In the 1800 United States presidential election, electors could be selected in each state at any time after October 31 and all electors were required to vote on December 3, 1800. In the 1800 United States presidential election in New York The state legislature chose 12 representatives, or electors to the Electoral College on November 6, 1800. [1] Based on the constitutional provision in effect at that time electors cast two votes. The candidate receiving most votes would be President. The runner up would be elected Vice President.

During this election, New York cast 12 electoral votes for Democratic-Republican Party candidates Thomas Jefferson and Aaron Burr. [2]

See also

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References

  1. https://founders.archives.gov/?q=%20Dates-From%3A1800-11-03&s=1111311111&r=8
  2. Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. p. 9. ISBN   9780786410170.