1800 United States presidential election in Kentucky

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1800 United States presidential election in Kentucky
  1796 October 31 – December 11, 1800 1804  
  Thomas Jefferson by Rembrandt Peale, 1800.jpg Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg
Nominee Thomas Jefferson John Adams
Party Democratic-Republican Federalist
Home state Virginia Massachusetts
Running mate Aaron Burr Charles C. Pinckney
Electoral vote40
Popular vote1190
Percentage100.00%0.00%

The 1800 United States presidential election in Kentucky took place between October 31 and December 11, 1800, as part of the 1800 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. [1]

Contents

Kentucky cast four electoral votes for the Democratic-Republican candidate and incumbent Vice President Thomas Jefferson over the Federalist candidate and incumbent President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. The state was divided into two electoral districts with two electors each, whereupon each district's voters chose the electors. [2]

Results

1800 United States presidential election in Kentucky [3]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Thomas Jefferson 119100.00%4
Federalist John Adams (incumbent)00.00%0
Totals119100.00%4

See also

References

  1. "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 14, 2023.
  2. "1800 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
  3. "1800 Presidential Election". 270towin.com. Retrieved July 14, 2023.