1792 United States presidential election in Kentucky

Main article: 1792 United States presidential election

1792 United States presidential election in Kentucky

November 2 – December 5, 1792 1796  →

Nominee George Washington Thomas Jefferson Party Independent Democratic-Republican Home state Virginia Virginia Electoral vote 4 4

The 1792 United States presidential election in Kentucky took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. It was the first presidential election Kentucky participated in since being admitted to the Union on June 1, 1792. ^[1]

Kentucky cast four electoral votes for the Independent candidate and incumbent President George Washington, as he ran effectively unopposed. The electoral votes for Vice president were cast for Democratic-Republican Thomas Jefferson from Virginia, the only state to do so. The state was divided into four electoral districts with one elector each, whereupon each district's voters chose the electors. ^[2]

Results

1792 United States presidential election in Kentucky [3]
Party		Candidate	Votes	Percentage	Electoral votes
	Independent	George Washington (incumbent)	–	–	4
Totals			–	–	4

See also

• United States presidential elections in Kentucky

References

1. Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. ISBN   9780786410170.
2. "1792 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
3. "1792 Presidential Election". 270towin.com. Retrieved July 14, 2023.