1792 United States presidential election in Kentucky

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1792 United States presidential election in Kentucky
November 2 – December 5, 1792 1796  
  George Washington Portrait (3x4 cropped).jpg Official Presidential portrait of Thomas Jefferson (by Rembrandt Peale, 1800) (3x4 cropped).jpg
Nominee George Washington Thomas Jefferson
Party Independent Democratic-Republican
Home state Virginia Virginia
Electoral vote44

The 1792 United States presidential election in Kentucky took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. It was the first presidential election Kentucky participated in since being admitted to the Union on June 1, 1792. [1]

Contents

Kentucky cast four electoral votes for the Independent candidate and incumbent President George Washington, as he ran effectively unopposed. The electoral votes for Vice president were cast for Democratic-Republican Thomas Jefferson from Virginia, the only state to do so. The state was divided into four electoral districts with one elector each, whereupon each district's voters chose the electors. [2]

Results

1792 United States presidential election in Kentucky [3]
PartyCandidateVotesPercentageElectoral votes
Independent George Washington (incumbent)4
Totals4

See also

References

  1. Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. ISBN   9780786410170.
  2. "1792 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
  3. "1792 Presidential Election". 270towin.com. Retrieved July 14, 2023.