1792 United States presidential election in Pennsylvania

Main article: 1792 United States presidential election

1792 United States presidential election in Pennsylvania

←  1788–89 November 2, 1792 – December 5, 1792 1796  →

Nominee George Washington John Adams George Clinton Party Independent Federalist Democratic-Republican Home state Virginia Massachusetts New York Electoral vote 15 14 1 Popular vote 3,396 – – Percentage 100% – –

County results Washington/Adams (Federalist)   50-60%   70-80%   90-100% Tie   50%

President before election George Washington Independent Elected President George Washington Independent

The 1792 United States presidential election in Pennsylvania took place as part of the 1792 United States presidential election. Pennsylvania voters chose 15 members of the Electoral College, ^[1] each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Pennsylvania unanimously voted for nonpartisan candidate and incumbent President George Washington. The two best performing electors in Pennsylvania, Joseph Hiester and William Henry, were supported by both parties. They received 3,396 and 3,371 votes respectively. It is not known which one voted for Clinton. ^[2] The total for Washington only includes the 3,396 number as to not represent Pennsylvanian voters twice in popular vote figures.

Results

1792 United States presidential election in Pennsylvania
Party		Candidate	Votes	Percentage	Electoral votes
	Independent	George Washington	3,396	100%	15
Totals			3,396	100%	15

See also

• List of United States presidential elections in Pennsylvania

References

1. "1792 ELECTION FOR THE SECOND TERM, 1793-1797". National Archives. Retrieved August 4, 2012.
2. "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 16, 2024.