1792 United States presidential election in Pennsylvania

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1792 United States presidential election in Pennsylvania
Flag of Pennsylvania.svg
  1788–89 November 2, 1792 – December 5, 1792 1796  
  Gilbert Stuart Williamstown Portrait of George Washington.jpg Jadams.jpeg George Clinton by Ezra Ames.jpg
Nominee George Washington John Adams George Clinton
Party Independent Federalist Democratic-Republican
Home state Virginia Massachusetts New York
Electoral vote15141
Popular vote3,396
Percentage100%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Pennsylvania took place as part of the 1792 United States presidential election. Pennsylvania voters chose 15 members of the Electoral College, [1] each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Contents

Pennsylvania unanimously voted for nonpartisan candidate and incumbent President George Washington. The two best performing electors in Pennsylvania, Joseph Hiester and William Henry, were supported by both parties. They received 3,396 and 3,371 votes respectively. It is not known which one voted for Clinton. [2] The total for Washington only includes the 3,396 number as to not represent Pennsylvanian voters twice in popular vote figures.

Results

1792 United States presidential election in Pennsylvania
PartyCandidateVotesPercentageElectoral votes
Independent George Washington 3,396100%15
Totals3,396100%15

See also

References

  1. "1792 ELECTION FOR THE SECOND TERM, 1793-1797". National Archives. Retrieved August 4, 2012.
  2. "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 16, 2024.