1824 United States presidential election in Pennsylvania

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1824 United States presidential election in Pennsylvania
Flag of Pennsylvania.svg
  1820 October 26 – December 2, 1824 1828  
  Andrew Jackson.jpg John Quincy Adams 1858 crop.jpg WilliamHCrawford.jpg
Nominee Andrew Jackson John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican Democratic-Republican
Home state Tennessee Massachusetts Georgia
Running mate John C. Calhoun John C. Calhoun Nathaniel Macon
Electoral vote2800
Popular vote35,9295,4364,182
Percentage76.04%11.50%8.85%

Pennsylvania Presidential Election Results 1824.png
County Results
Jackson
  50-60%
  60-70%
  70-80%
  80-90%
  90-100%

The 1824 United States presidential election in Pennsylvania took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 28 representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

During this election, the Democratic-Republican Party was the only major national party, and 4 different candidates from this party sought the Presidency. Pennsylvania voted for Andrew Jackson over John Quincy Adams, William H. Crawford, and Henry Clay. Jackson won Pennsylvania by a wide margin of 64.54%. To date, this is the Democratic Party's best performance in Pennsylvania.

This is the only time any presidential candidate has swept every Pennsylvania county.

Results

1824 United States presidential election in Pennsylvania [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Andrew Jackson 35,92976.04%28
Democratic-Republican John Quincy Adams 5,43611.50%0
Democratic-Republican William H. Crawford 4,1828.85%0
Democratic-Republican Henry Clay 1,7053.61%0
Totals47,252100.0%28

See also

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References

  1. "1824 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.