1824 United States presidential election in Connecticut

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1824 United States presidential election in Connecticut
Flag of Connecticut.svg
  1820 October 26 – December 2, 1824 1828  
  John Quincy Adams 1858 crop.jpg WilliamHCrawford.jpg
Nominee John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Massachusetts Georgia
Running mate John C. Calhoun Nathaniel Macon
Electoral vote80
Popular vote7,4941,965
Percentage70.39%18.46%

Connecticut Presidential Election Results 1824.svg
County Results
Adams
  60–70%
  70–80%
  80–90%
  90–100%

The 1824 United States presidential election in Connecticut took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Connecticut voted for John Quincy Adams over William H. Crawford, Andrew Jackson, and Henry Clay. Adams won Connecticut by a margin of 51.93%.

Results

1824 United States presidential election in Connecticut [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican John Quincy Adams 7,49470.39%8
Democratic-Republican William H. Crawford 1,96518.46%0
N/AOther1,18811.16%0
Totals10,647100.0%8

See also

References

  1. "1824 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved February 27, 2013.