1836 United States presidential election in Connecticut

Main article: 1836 United States presidential election

1836 United States presidential election in Connecticut

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Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard M. Johnson Francis Granger Electoral vote 8 0 Popular vote 19,294 18,799 Percentage 50.65% 49.35%

County Results Van Buren   50–60% Harrison   50–60%

A presidential election was held in Connecticut on November 7, 1836 as part of the 1836 United States presidential election. ^[1] Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.

As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.

Results

1836 United States presidential election in Connecticut [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	19,294	50.65%	8
	Whig	William Henry Harrison	18,799	49.35%	0
Totals			38,093	100.0%	8

See also

• United States presidential elections in Connecticut

References

1. "Presidential Elections". Weekly Messenger. November 12, 1836.
2. "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved August 4, 2012.