1836 United States presidential election in New Hampshire

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1836 United States presidential election in New Hampshire
Flag of New Hampshire.svg
  1832 November 3 - December 7, 1836 1840  
  Martin Van Buren circa 1837 crop.jpg William Henry Harrison by James Reid Lambdin, 1835 crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Mentor Johnson Francis Granger
Electoral vote70
Popular vote18,6976,228
Percentage75.01%24.99%

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%. As of 2020, this remains the strongest ever performance by any presidential candidate in New Hampshire since the creation of the modern Democratic party in 1828.

Results

1836 United States presidential election in New Hampshire [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 18,69775.01%7100.00%
Whig William Henry Harrison of Ohio Francis Granger of New York 6,22824.99%00.00%
Total24,925100.00%7100.00%

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References

  1. "1836 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved 23 December 2013.