1836 United States presidential election in New Hampshire

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1836 United States presidential election in New Hampshire
Flag of New Hampshire.svg
  1832 November 7, 1836 1840  
  MO
TN  
  Martin Van Buren circa 1837 crop.jpg William Henry Harrison by James Reid Lambdin, 1835 crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard M. Johnson Francis Granger
Electoral vote70
Popular vote18,6976,228
Percentage75.01%24.99%

New Hampshire Presidential Election Results 1836.svg
County Results
Van Buren
  50–60%
  60–70%
  70–80%
  80–90%

A presidential election was held in New Hampshire on November 7, 1836 as part of the 1836 United States presidential election. [1] Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%. As of 2020, this remains the strongest ever performance by any presidential candidate in New Hampshire since the creation of the modern Democratic party in 1828.

Results

1836 United States presidential election in New Hampshire [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 18,69775.01%7100.00%
Whig William Henry Harrison of Ohio Francis Granger of New York 6,22824.99%00.00%
Total24,925100.00%7100.00%

See also

References

  1. "Presidential Elections". Weekly Messenger. November 12, 1836.
  2. "1836 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.