1860 United States presidential election in New Hampshire

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1860 United States presidential election in New Hampshire
Flag of New Hampshire.svg
  1856 November 2, 1860 1864  
  Abraham Lincoln by Alexander Hesler, 1860-restored (cropped).png Senator Stephen A. Douglas (edited).png
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote50
Popular vote37,51925,887
Percentage56.90%39.26%

New Hampshire Presidential Election Results 1860.svg
County Results
Lincoln
  40-50%
  50-60%
  60-70%

The 1860 United States presidential election in New Hampshire took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for president and vice president.

Contents

New Hampshire was won by Republican candidate Abraham Lincoln, who won the state by 17.64%.

Results

1860 United States presidential election in New Hampshire [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 37,51956.90%5100.00%
Democratic Stephen Arnold Douglas of Illinois Herschel Vespasian Johnson of Georgia 25,88739.26%00.00%
Southern Democratic John Cabell Breckinridge of Kentucky Joseph Lane of Oregon 2,1253.22%00.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 4120.62%00.00%
Total65,943100.00%5100.00%

See also

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References

  1. "1860 Presidential General Election Results - New Hampshire".