1860 United States presidential election in Wisconsin

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1860 United States presidential election in Wisconsin
Flag of the United States (1859-1861).svg
  1856 November 6, 1860 1864  
  Abraham Lincoln by Alexander Hesler, 1860-restored (cropped).png Senator Stephen A. Douglas (edited).png
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote50
Popular vote86,11365,021
Percentage56.59%42.73%

Wisconsin Presidential Election Results 1860.svg
County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Wisconsin was held on November 6, 1860, as part of the 1860 United States presidential election. State voters chose five electors to the Electoral College, who voted for president and vice president.

Contents

Wisconsin was won by the Republican Party candidate Abraham Lincoln and his running mate Hannibal Hamlin. They defeated the Democratic Party candidate Stephen A. Douglas and his running mate Herschel V. Johnson. Lincoln won the state by a margin of 13.86%.

Results

1860 United States presidential election in Wisconsin [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 86,11356.59%5100.00%
Democratic Stephen Arnold Douglas of Illinois Herschel Vespasian Johnson of Georgia 65,02142.73%00.00%
Southern Democratic John Cabell Brekinridge of Kentucky Joseph Lane of Oregon 8880.58%00.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 1610.11%00.00%
Total152,183100.00%5100.00%

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References

  1. "1860 Presidential General Election Results - Wisconsin".