1860 United States presidential election in Alabama

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1860 United States presidential election in Alabama
Flag of Alabama.svg
  1856 November 6, 1860 1868  
  John C Breckinridge-04775-restored.jpg John Bell (Restored).png Senator Stephen A. Douglas (edited).png
Nominee John C. Breckinridge John Bell Stephen A. Douglas
Party Southern Democratic Constitutional Union Democratic
Home state Kentucky Tennessee Illinois
Running mate Joseph Lane Edward Everett Herschel V. Johnson
Electoral vote900
Popular vote48,66927,83513,618
Percentage54.00%30.89%15.11%

Alabama Presidential Election Results 1860.png
County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

The 1860 United States presidential election in Alabama took place on November 6, 1860, as part of the 1860 United States presidential election. Alabama voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.

Contents

Alabama was won by the Southern Democratic candidate 14th Vice President of the United States John C. Breckinridge of Kentucky and his running mate Senator Joseph Lane of Oregon. They defeated the Constitutional Union candidate Senator John Bell of Tennessee and his running mate Governor of Massachusetts Edward Everett as well as the Democratic candidate 15th Senator Stephen A. Douglas of Illinois) and his running mate 41st Governor of Georgia Herschel V. Johnson. Breckinridge would win the state by a margin of 23.11%.

Republican Party candidate Abraham Lincoln was not on the ballot in the state. It would not participate in the 1864 election, which Lincoln won.

Results

1860 United States presidential election in Alabama [1]
PartyCandidateVotes%
Southern Democratic John C. Breckinridge 48,669 54.00%
Constitutional Union John Bell 27,83530.89%
Democratic Stephen A. Douglas 13,61815.11%
Total votes90,122 100.00%

See also

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References

  1. "1860 Presidential Election Results Alabama".