1836 United States presidential election in Alabama

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1836 United States presidential election in Alabama
Flag of Alabama.svg
  1832 November 3 – December 7, 1836 1840  
  Martin Van Buren circa 1837 crop.jpg HLWhite.jpg
Nominee Martin Van Buren Hugh White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard Johnson John Tyler
Electoral vote70
Popular vote20,63816,658
Percentage55.34%44.66%

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

The 1836 United States presidential election in Alabama took place between November 3 and December 7, 1836, as part of the 1836 presidential election. Voters chose seven representatives, or electors, to the Electoral College, who voted for President and Vice President.

Contents

Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Alabama by a margin of 10.68%.

Results

1836 United States presidential election in Alabama [1]
PartyCandidateVotesPercentageElectoral votes
Democratic Martin Van Buren 20,63855.34%7
Whig Hugh White 16,65844.66%0
Totals37,296100.00%7

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References

  1. "1836 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved August 4, 2012.