1836 United States presidential election in Virginia

Main article: 1836 United States presidential election

1836 United States presidential election in Virginia

←  1832 November 7, 1836 1840  →

←  TN MI  →

Nominee Martin Van Buren Hugh L. White Party Democratic Whig Home state New York Tennessee Running mate William Smith John Tyler Electoral vote 23 0 Popular vote 30,556 23,384 Percentage 56.64% 43.35%

County results Van Buren   50–60%   60–70%   70–80%   80–90%   90–100% White   50–60%   60–70%   70–80%   80–90%   90–100%

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

A presidential election was held in Virginia on November 7, 1836 as part of the 1836 United States presidential election. ^[1] Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Virginia by a margin of 13.29%. While Van Buren's national running mate was Richard Mentor Johnson, the Virginia Democratic electors refused to support his candidacy and voted for William Smith of South Carolina.

Results

United States presidential election in Virginia, 1836 [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	30,556	56.64%	23
	Whig	Hugh L. White	23,384	43.35%	0
	N/A	Others	5	0.01%	0
Totals			53,945	100.00%	23

References

1. "Presidential Elections". Weekly Messenger. November 12, 1836.
2. "1836 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved April 12, 2013.