1840 United States presidential election in Virginia

Main article: 1840 United States presidential election

1840 United States presidential election in Virginia

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Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard M. Johnson John Tyler Electoral vote 23 0 Popular vote 43,757 42,637 Percentage 50.65% 49.35%

County Results Van Buren   50-60%   60-70%   70-80%   80-90%   90-100% Harrison   50-60%   60-70%   70–80%   80-90%   90–100%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

A presidential election was held in Virginia on November 2, 1840 as part of the 1840 United States presidential election. ^[1] Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia voted for the Democratic candidate, incumbent President Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren narrowly won Virginia by a margin of 1.3%, or 1,120 votes.

Results

1840 United States presidential election in Virginia [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren (inc.)	43,757	50.65%	23
	Whig	William Henry Harrison	42,637	49.35%	0
Totals			86,394	100.0%	23

References

1. Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
2. "1840 Presidential General Election Results - Virginia". U.S. Election Atlas. Archived from the original on June 19, 2015. Retrieved April 12, 2013.