1840 United States presidential election in Connecticut

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1840 United States presidential election in Connecticut
Flag of Connecticut.svg
  1836 November 2, 1840 1844  
  AR
GA  
  William Henry Harrison crop.jpg Martin Van Buren circa 1837 crop.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote80
Popular vote31,59825,281
Percentage55.55%44.45%

Connecticut Presidential Election Results 1840.svg
Connecticut Presidential Election Results by CD 1840.svg
County Results
Harrison
  40–50%
  50–60%

A presidential election was held in Connecticut on November 2, 1840 as part of the 1840 United States presidential election. [1] Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Connecticut voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Connecticut by a margin of 11.1%.

Results

1840 United States presidential election in Connecticut [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Whig William Henry Harrison of Ohio John Tyler of Virginia 31,59855.55%8100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 25,28144.45%00.00%
Total56,879100.00%8100.00%

See also

References

  1. Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
  2. "1840 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved December 23, 2013.