1828 United States presidential election in Connecticut

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1828 United States presidential election in Connecticut
Flag of Connecticut.svg
  1824 October 31 – December 2, 1828 1832  
  John Quincy Adams 1858 crop.jpg Andrew Jackson.jpg
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote80
Popular vote13,8294,448
Percentage71.36%22.95%

Connecticut Presidential Election Results 1828.svg
County Results
Adams
  60–70%
  70–80%
  80–90%

The 1828 United States presidential election in Connecticut took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Connecticut voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Connecticut by a margin of 48.41%.

With 71.36% of the popular vote, Connecticut would prove to be Adams' fourth strongest state in the 1828 election after Rhode Island, Massachusetts and Vermont. [1]

Results

1828 United States presidential election in Connecticut [2]
PartyCandidateVotesPercentageElectoral votes
National Republican John Quincy Adams (incumbent)13,82971.36%8
Democratic Andrew Jackson 4,44822.95%0
N/AOther1,1015.68%0
Totals19,378100.0%8

See also

References

  1. "1828 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. "1828 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved February 28, 2013.