1884 United States presidential election in Connecticut

Main article: 1884 United States presidential election

1884 United States presidential election in Connecticut

←  1880 November 4, 1884 1888  →

Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 6 0 Popular vote 67,182 65,898 Percentage 48.95% 48.01%

County Results Municipality Results Cleveland   40–50%   50–60%   60–70%   70–80% Blaine   50–60%   60–70%   70–80%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

The 1884 United States presidential election in Connecticut took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Connecticut voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a very narrow margin of 0.94%. Cleveland was the first Democrat to win without New London County since 1844 and Middlesex County since 1832.

Results

1884 United States presidential election in Connecticut [1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	67,182	48.95%	6	100.00%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	65,898	48.01%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	2,493	1.82%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	1,684	1.23%	0	0.00%
Total				137,257	100.00%	6	100.00%

See also

• United States presidential elections in Connecticut

References

1. "1884 Presidential General Election Results - Connecticut".