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April 2, 1849 | |||||||||||||||||||||||||
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  Trumbull: 30–40% 40–50% 50–60% 60–70% 70–80% Seymour: 30–40% 40–50% 50–60% 60–70% 70–80% Tie: 40-50% | |||||||||||||||||||||||||
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| Elections in Connecticut |
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The 1849 Connecticut gubernatorial election was held on April 2, 1849. [1] Former congressman and Whig nominee Joseph Trumbull defeated former congressman and Democratic nominee Thomas H. Seymour as well as former Senator and Free Soil nominee John M. Niles with 49.35% of the vote. Niles had previously been the Democratic nominee for this same office in 1840.
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Trumbull won a plurality of the vote, but fell short of a majority. As a result, the Connecticut General Assembly elected the governor, per the state constitution. Trumbull won the vote over Seymour 122 to 110 in the General Assembly, and became the governor. [2] This was the first of six consecutive elections in which the Free Soil Party participated.
