1884 United States presidential election in Louisiana

Main article: 1884 United States presidential election

1884 United States presidential election in Louisiana

←  1880 November 4, 1884 1888  →

Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 7 0 Popular vote 62,594 46,347 Percentage 57.22% 42.37%

Parish Results Cleveland   50–60%   60–70%   70–80%   80–90%   90–100% Blaine   50–60%   60–70%   70–80%   80–90%   90–100%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

The 1884 United States presidential election in Louisiana took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. State voters chose eight electors to the Electoral College, which selected the president and vice president.

Louisiana voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 14.85%.

Results

1884 United States presidential election in Louisiana [1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	62,594	57.22%	8	100.00%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	46,347	42.37%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	338	0.31%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	120	0.11%	0	0.00%
Total				109,399	100.00%	8	100.00%

See also

• United States presidential elections in Louisiana

References

1. "1884 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved November 25, 2020.