1852 United States presidential election in Louisiana

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1852 United States presidential election in Louisiana
Flag of Louisiana.svg
  1848 November 2, 1852 1856  
  Mathew Brady - Franklin Pierce (cropped).jpg Winfield Scott by Fredricks, 1862 (cropped).jpg
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote60
Popular vote18,64717,255
Percentage51.94%48.06%

Louisiana Presidential Election Results 1852.svg
Parish results

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Louisiana took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Louisiana voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Louisiana by a narrow margin of 3.88%.

Results

1852 United States presidential election in Louisiana [1] [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 18,64751.94%6100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 17,25548.06%00.00%
Total35,902100.00%6100.00%

See also

References

  1. "1852 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved December 2, 2017.
  2. "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 2, 2017.