1852 United States presidential election in Arkansas

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1852 United States presidential election in Arkansas
Flag of Arkansas.svg
  1848 November 2, 1852 1856  
  Mathew Brady - Franklin Pierce (cropped).jpg Winfield Scott by Fredricks, 1862 (cropped).jpg
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote40
Popular vote12,1737,404
Percentage62.18%37.82%

Arkansas Presidential Election Results 1852.svg
County Results

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Arkansas took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Arkansas voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Arkansas by a margin of 24.36%.

Results

1852 United States presidential election in Arkansas [1] [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 12,17362.18%4100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 7,40437.82%00.00%
Total19,577100.00%4100.00%

See also

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References

  1. "1852 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved December 1, 2017.
  2. "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 1, 2017.