1884 United States presidential election in Arkansas

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1884 United States presidential election in Arkansas
Flag of Arkansas.svg
  1880 November 4, 1884 1888  
  StephenGroverCleveland.jpg Unsuccessful 1884.jpg
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote70
Popular vote72,73451,198
Percentage57.83%40.70%

Arkansas Presidential Election Results 1884.svg
County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Arkansas took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. Arkansas voters chose seven electors to the Electoral College, which selected the president and vice president.

Contents

Arkansas voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 17.12%.

Results

1884 United States presidential election in Arkansas [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 72,73457.83%7100.00%
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 51,19840.70%00.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 1,8471.47%00.00%
Total125,779100.00%7100.00%

See also

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References

  1. "1884 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved November 25, 2020.