1884 United States presidential election in Indiana

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1884 United States presidential election in Indiana
Flag of Indiana.svg
  1880 November 4, 1884 1888  
  StephenGroverCleveland.jpg Unsuccessful 1884.jpg
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote150
Popular vote245,005238,489
Percentage49.46%48.15%

Indiana Presidential Election Results 1884.svg
County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

A presidential election was held in Indiana on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Indiana voted for the Democratic nominee, Grover Cleveland over the Republican nominee, James G. Blaine. Cleveland won the state by a narrow margin of 1.31%.

Results

1884 United States presidential election in Indiana [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 245,00549.46%15100.00%
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 238,48948.15%00.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 8,8101.78%00.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 3,0280.61%00.00%
Total495,332100.00%15100.00%

See also

References

  1. "1884 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved December 23, 2013.