1864 United States presidential election in Indiana

Main article: 1864 United States presidential election

1864 United States presidential election in Indiana

←  1860 November 8, 1864 1868  →

Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois New Jersey Running mate Andrew Johnson George H. Pendleton Electoral vote 13 0 Popular vote 150,422 130,233 Percentage 53.60% 46.40%

County Results Lincoln   50–60%   60–70%   70–80%   80–90% McClellan   50–60%   60–70%   70–80%   80–90%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln National Union

A presidential election was held in Indiana on November 8, 1864, as part of the 1864 United States presidential election. Indiana voters chose 13 representatives, or electors, to the Electoral College, who voted for president and vice president. ^[1]

Indiana was won by the National Union candidate, incumbent Republican President Abraham Lincoln of Illinois and his running mate former Senator and Military Governor of Tennessee Andrew Johnson. They defeated the Democratic candidate, 4th Commanding General of the United States Army George B. McClellan of New Jersey and his running mate Representative George H. Pendleton of Ohio. Lincoln won the state by a margin of 7.2%. ^[1]

Results

1864 United States presidential election in Indiana [1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	National Union	Abraham Lincoln of Illinois	Andrew Johnson of Tennessee	150,422	53.60%	13	100.00%
	Democratic	George B. McClellan of New Jersey	George H. Pendleton of Ohio	130,233	46.40%	0	0.00%
Total				280,655	100.00%	13	100.00%

See also

• United States presidential elections in Indiana

References

1. "1864 Presidential Election Results Indiana".