1864 United States presidential election in Pennsylvania

Main article: 1864 United States presidential election

1864 United States presidential election in Pennsylvania

←  1860 November 8, 1864 1868  →

Nominee Abraham Lincoln George B. McClellan Party National Union Democratic Home state Illinois New Jersey Running mate Andrew Johnson George H. Pendleton Electoral vote 26 0 Popular vote 296,391 276,316 Percentage 51.75% 48.25%

County Results Lincoln   50–60%   60–70%   70–80% McClellan   50–60%   60–70%   70–80%   80–90%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln National Union

The 1864 United States presidential election in Pennsylvania took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for president and vice president.

Pennsylvania voted for the National Union candidate, incumbent Republican President Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate, George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a narrow margin of 3.5%.

Results

1864 United States presidential election in Pennsylvania [1]
Party		Candidate	Votes	Percentage	Electoral votes
	National Union	Abraham Lincoln (incumbent)	296,391	51.75%	26
	Democratic	George B. McClellan	276,316	48.25%	0
Totals			572,707	100.0%	26

See also

• List of United States presidential elections in Pennsylvania

References

1. "1864 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 3, 2012.